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The ratio of SF under independence to SF when both treatments are applied simultaneously

Posted by ywang567 on 15 Dec 2020 at 21:09 GMT

In the "Example: Daphnia acute test with CuSO4 and NiCl" section, the paper mentioned "the ratio of SF under independence to SF when both treatments are applied simultaneously is exp(y1 + y2 − y3) = 1.168"- should this ratio be calculated as mean(A)*mean(B)/mean(D) where A, B, and D are the SFs with the applications of drug A, drug B, and the combination of drug A and B, respectively? In the R code, y1=mean[log(A)], y2=mean[log(B)], y3=mean[log(D)], and exp(y1 + y2 − y3) would not equal to mean(A)*mean(B)/mean(D) (calculated as 1.16025 in this case).

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